Tuesday, 9 June 2020

listing files from directorwy with php

listing files from directorwy with php
Iam at parent directory ,in this image and fliephp files are there, from this place , I want to read whats the files are there in he image director, and before this parent/images/1.jpg
file.php
every folder consists some files , called directory
open dir - uysing this we can open the directory and ready to execute
read dir - using this we can read each and every element in directory
how to print the names of the images inside the directory with extension
</php
images/ or second argument is slash
$directory = 'images';
variable name created
if (@opendir($directory. '/') {
used @ for , if this fails, it wil print some error commands, to remove that use @
echo 'Looking inside <strong' .$directory .'</strong> .: <br>';
}
looking inside the images
else {
it will print we eare looking , it the files in not there, it shows cannot be opened
echo $Director. 'cannot be opened';
}
how to print with directory two dots of the images in directory
</php
$directory = 'images';
if (@$folder = opendir($directory. '/') {
takes the directory data to folde variable
echo 'Looking inside <strong' .$directory .'</strong> .: <br>';
prints the data insde the director
while ($file = readdir ($folder){
with readdir- refers each and every file in that directory
echo $file .'<br>';
each file prints and go t o initial
}
else {
imag
echo $Director. 'cannot be opened';
if not there , can not be opened
}
image
it wil print with directory dots also
how to print without directory two dots of the images in directory
</php
$directory = 'images';
images string went to directory variable
if (@$folder = opendir($directory. '/') {
it will open the images directory means ready to execute
echo 'Looking inside <strong' .$directory .'</strong> .: <br>';
prints looking insde the images
while ($file = readdir ($folder0){
next exeute next thing , go to each and every line in directory
if($file !='.'  && $file != '..'){
it wll chek if it is not equal,, then prints the image shows with change in width
echo '<img src = "'.$directory.'/'.$file.'" width ='300" heiaght= "300"><br><br>';
}
}
else {
echo $Director. 'cannot be opened';
}
opendir
at@
ifelse
concatenation
opendir
opendir
if else
while
if else
concatenation
notequal
how to open the directory
if opened , print it is opened 
how to print with directory two dots of the images in directory
how to open the directory
how to read the each and every eleemtn in directory
how to show the image in html page from the directory 


No comments:

Post a Comment